Answer: 53, 54, 55, and 56
Step-by-step explanation: This problem states that the sum of 4 consecutive numbers is 218 and it asks us to find the numbers.
4 consecutive numbers can be represented as followed.
X ⇒ <em>first number</em>
X + 1 ⇒ <em>second number</em>
X + 2 ⇒ <em>third number</em>
X + 3 ⇒ <em>fourth number</em>
Since the sum of our 4 consecutive numbers is 218, we can set up an equation to represent this.
X + X + 1 + X + 2 + X + 3 = 218
On the left side of the equation, we can combine our x's and our numbers.
4x + 6 = 218
-6 -6 ← <em><u>subtract 6 from both sides of the equation</u></em>
4x = 212
÷4 ÷4 ← <u><em>divide both sides of the equation by 4</em></u>
<u>X = 53</u>
<u />
X ⇒ <em>first number = 53</em>
X + 1 ⇒ <em>second number = 54</em>
X + 2 ⇒ <em>third number = 55</em>
X + 3 ⇒ <em>fourth number = 56</em>
<em />
<em>Therefore, our 4 consecutive numbers are </em><em>53</em><em>, </em><em>54</em><em>, </em><em>55</em><em>, and </em><em>56</em><em>.</em>
