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SVEN [57.7K]
2 years ago
12

(Look at screenshot)

Mathematics
1 answer:
True [87]2 years ago
8 0

#1

Clear shown in graph

  • H(0)=5

#2

No

At. no where graph passes through origin so y intercept is not 0 at anywhere

#3

Domain is x values

  • Domain =[0,oo)

#4

Range is y values set

  • Range=[5,50]
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A mother has two apples, three pears, and four oranges. She plans to give her son one piece of fruit every morning for nine days
Olin [163]

Answer:

Umm nine ways?

Step-by-step explanation:

5 0
2 years ago
The graph shows the yearly balance, in dollars, in an investment account.
Temka [501]

Take 2 points

  • (0,5000)
  • (2,4000)

Slope:-

\\ \rm\Rrightarrow m=\dfrac{4000-5000}{2}=-500

Equation in point slope form

\\ \rm\Rrightarrow y-5000=-500(x)

\\ \rm\Rrightarrow y=-500x+5000

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6 0
2 years ago
17 please help me......................
Vaselesa [24]
I think its (6.5+3.25)÷0.2=48.75

dont quote me on that, I tried and I'm not the best at math lol.
(6.5 + 3.25) \div 0.2
8 0
3 years ago
Please help me i dont know what the answer is ??
Assoli18 [71]
To answer this, we need to use the rules of geometric shapes. An equilateral triangle is equiangular, meaning all its angle measures are equal. Since all triangles' angles add up to 180°, simply divide 180 by three to find the angle measure of each angle:
\frac{180}{3} = 60
Therefore, the measure of the triangle's angle is 60°

Next, we know that a characteristic of a rectangle is that each angle must be a right angle, or an angle with a measure of 90°.

Now, all we have to do is use the sum of all the angle measures to figure out the missing piece:
90=x+60+12 \\ 90=x+72 \\ 90-72=(x+72)-72 \\ 18=x

The missing angle measure, angle x, equals 18°.

Hope this helps!
7 0
3 years ago
A company can manufacture x hundred items for a total cost of C=300+1200x-100x. Find x if the total cost is 3,000
Scilla [17]
C=300+1200x-100x. Find x if the total cost is 3,000
3,000 = 300 + 1200x -100x
3000 = 300 + 1100x
2700 = 1100x
2700÷1100=x
x=27/11
x = 2 5/11 Round to 3
5 0
3 years ago
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