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2 years ago

(Look at screenshot)

Mathematics

1 answer:

True [87]2 years ago

8 0

Clear shown in graph

H(0)=5

At. no where graph passes through origin so y intercept is not 0 at anywhere

Domain is x values

Domain =[0,oo)

Range is y values set

Range=[5,50]

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Miguels employer pays $1,825 in health insurance and 593 in life insurance per year. He also gets $2,860 in paid time off per

Luden [163]

I think that it’s c 58.668 I don’t know I’m really don’t sure I wish you the best of luck

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3 years ago

If m<FHI=142, what are m<FHG and m<GHI

lisabon 2012 [21]

<h3>Answers:</h3>

angle FHG = 42 degrees

angle GHI = 100 degrees

=========================================================

Explanation:

FHI is the largest angle. It is split into two pieces FHG and GHI which have measures of (3x+6) and (9x-8) degrees respectively.

Put another way, those two smaller angles (FHG and GHI) combine to form the larger angle (FHI)

This is the angle addition postulate.

------------------

(angle FHG) + (angle GHI) = angle FHI

(3x+6) + (9x-8) = 142

3x+6+9x-8 = 142

(3x+9x) + (6-8) = 142

12x - 2 = 142

12x-2+2 = 142+2 ... adding 2 to both sides

12x = 144

12x/12 = 144/12 .... dividing both sides by 12

x = 12

------------------

Use that x value to find the angles we're after

angle FHG = 3x+6 = 3*12+6 = 36+6 = 42

angle GHI = 9x-8 = 9*12-8 = 108-8 = 100

Note how

(angle FHG) + (angle GHI) = 42 + 100 = 142

which is the measure of angle FHI. This confirms the answers.

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2 years ago

Tom hits golf balls at the driving range every 3 days, practices putting every 4days, and goes golfing every 6 days. If he did a

anygoal [31]

Answer:

12 days

Step-by-step explanation:

Trust me I did the work.

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3 years ago

A farmer with 5000 feet of fencing wants to enclose a rectangular field and then divide it into two plots by adding a fence in t

matrenka [14]

Answer:

The required width of the field that would maximize the area is = 1250 feet

Step-by-step explanation:

Given that:

The total fencing length = 5000 ft

Let consider w to be the width and L to be the length.

Then; the perimeter of the rectangular field by assuming a parallel direction is:

P = 3L + 2w

⇒ 3L + 2w = 5000

3L = 5000 - 2w

$L = \dfrac{5000}{3} - \dfrac{2w}{3}$

Recall that:

The area of the rectangle = L×w

$A(w) = ( \dfrac{5000}{3}-\dfrac{2}{3} ) w$

$A(w) = \dfrac{5000}{3}w-\dfrac{2}{3} w^2$

Taking the differentiation of both sides with respect to t; we have:

$A' (w) = \dfrac{5000}{3} - \dfrac{2}{3} ( 2 w)$

$A' (w) = \dfrac{5000}{3} - \dfrac{4w}{3}$

Then; we set A'(w) to be equal to zero;

So; $\dfrac{5000}{3} - \dfrac{4w}{3}=0$

5000 = 4w

w = 5000/4

w = 1250

Thus; the required width of the field that would maximize the area is = 1250 feet

Also, the length $L = \dfrac{5000}{3} - \dfrac{2w}{3}$ can now be :

$L = \dfrac{5000}{3} - \dfrac{2(1250)}{3}$

L = (5000 -2500)/3

L = 2500/3 feet

Suppose, the farmer divides the plot parallel to the width; Then 2500/3 feet = 833.33 feet and the length L = 1250 feet.

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2 years ago

If y varies directly as x, and y = 12 when x = 4, what is the value of y when x = 7 ?

Tamiku [17]

Answer:21

(7*12)/4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers