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saw5 [17]
2 years ago
10

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the leng

th of B C is 24.
Given right triangle ABC, what is the value of tan(A)?
Mathematics
2 answers:
Leto [7]2 years ago
6 0

Answer:

<h2><u><em>tan(A) = 12/5</em></u></h2>

Step-by-step explanation:

Given a right angle triangle ABC.

If ∠BCA = 90°

the hypotenuse AB = 26

AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

Tan (A) = opp/adj

Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;

tan(A) = BC/AC

tan(A) = 24/10

tan(A) = 12/5

Valentin [98]2 years ago
3 0

Answer:

         \ tan \ A = \dfrac{24}{10}

Step-by-step explanation:

\sf Tan \ A = \dfrac{opposite \ side \ of \ angle \ A}{adjacent \ side \ of \ angle A}\\\\Tan \ A = \dfrac{BC}{AC}\\\\Tan \ A = \dfrac{24}{10}

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Sauron [17]

Answer:

Here is the answer with the steps

Step-by-step explanation:

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3 0
3 years ago
Find the prime factorization for the number m (if possible) that makes each of the following true. If no number is possible, exp
SSSSS [86.1K]

Answer:

Is not possible to find a prime factorization for m.

Step-by-step explanation:

if

2^3 . 19^5 . 23^4 = 2^3 . 19^5 . 46 . m

then

m=\frac{2^3. 19^5 . 23^4}{2^3 . 19^5 . 46 }=\frac{2^3. 19^5 . 23^4}{2^3 . 19^5 . 2.23 }=\frac{23^3}{2}

So m is not an integer, hence it cannot be decomposed in prime factors.

3 0
3 years ago
Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

6 0
3 years ago
Read 2 more answers
Use a system of equations to solve this problem.Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bron
d1i1m1o1n [39]

Answer:

x = 50 grs

y = 50 grs

Step-by-step explanation:

" x "   is quantity of bronze of 5% tin

" y "   is quantity of bronze of 45% tin

The worker needs 100 grs of bronze and this bronze must be 25% tin

The mathematical expression for the 100 grs condition is:

x + y = 100

And the The mathematical expression for the % condition is:

0,05*x  + 0.45*y  = 0,25 * ( x + y )

The system is:

x + y = 100

0,05*x + 0,45*y = 0,25* ( x + y )

Solving this system we get values of x and y

y = 100 - x

0,05*x  + 0,45* ( 100 - x ) = 0,25 * ( x + 100 - x )

0,05*x  + 45 - 0,45*x = 0,25*( 100 )

0,05*x  + 45 - 0,45*x  = 25

- 0,4*x  = -45 + 25

x = 20/0,4            x = 50  grs

and y = 50 grs

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Please help and add steps!!
Veseljchak [2.6K]

Answer:

so what yhu want to do is 9 times 3  than 5y times 37

Step-by-step explanation:

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