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Butoxors [25]
3 years ago
9

Charles has $20 to spend at the bakery he wants to buy six cupcakes and a pie. The pie costs

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0
The most he can buy for each cupcake is 1.25
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A sequence is defined recursively by
Andrei [34K]

9514 1404 393

Answer:

  an = 4×34^(n-1)

Step-by-step explanation:

If your recursive definition is ...

  \begin{cases}a_1=4\\a_{n}=34a_{n-1}\end{cases}

this defines a geometric sequence with a first term a1 = 4 and a common ratio of r = 34. The general form of the explicit function is ...

  a_n=a_1\times r^{n-1}

For the values shown here, the explicit definition of the sequence is ...

  \boxed{a_n=4\times 34^{n-1}}

8 0
2 years ago
Maths functions <br> please help!
Vlad [161]

Answer:

\textsf{1)} \quad f(x)=-x+3

2)   A = (3, 0)  and C = (-3, 0)

\textsf{3)} \quad g(x)=x^2-9

4)  AC = 6 units and OB = 9 units

Step-by-step explanation:

Given functions:

\begin{cases}f(x)=mx+c\\g(x)=ax^2+b \end{cases}

<h3><u>Part (1)</u></h3>

Given points:

  • H = (-1, 4)
  • T = (4, -1)

As points H and T lie on f(x), substitute the two points into the function to create two equations:

\textsf{Equation 1}: \quad f(-1)=m(-1)+c=4 \implies -m+c=4

\textsf{Equation 2}: \quad f(4)=m(4)+c=-1 \implies 4m+c=-1

Subtract the first equation from the second to eliminate c:

\begin{array}{r l} 4m+c & = -1\\- \quad -m+c & = \phantom{))}4\\\cline{1-2}5m \phantom{))))}}& = -5}\end{aligned}

Therefore m = -1.

Substitute the found value of m and one of the points into the function and solve for c:

\implies f(4)=-1(4)+c=-1

\implies c=-1-(-4)=3

Therefore the equation for function f(x) is:

f(x)=-x+3

<h3><u>Part (2)</u></h3>

Function f(x) crosses the x-axis at point A.  Therefore, f(x) = 0 at point A.

To find the x-value of point A, set f(x) to zero and solve for x:

\implies f(x)=0

\implies -x+3=0

\implies x=3

Therefore, A = (3, 0).

As g(x) = ax² + b, its axis of symmetry is x = 0.

A parabola's axis of symmetry is the midpoint of its x-intercepts.

Therefore, if A = (3, 0) then C = (-3, 0).

<h3><u>Part (3)</u></h3>

Points on function g(x):

  • A = (3, 0)
  • G = (1, -8)

Substitute the points into the given function g(x) to create two equations:

\textsf{Equation 1}: \quad g(3)=a(3)^2+b=0 \implies 9a+b=0

\textsf{Equation 2}: \quad g(1)=a(1)^2+b=-8 \implies a+b=-8

Subtract the second equation from the first to eliminate b:

\begin{array}{r l} 9a+b & =  \phantom{))}0\\- \quad a+b & =-8\\\cline{1-2}8a \phantom{))))}}& =  \phantom{))}8}\end{aligned}

Therefore a = 1.

Substitute the found value of a and one of the points into the function and solve for b:

\implies g(3)=1(3^2)+b=0

\implies 9+b=0\implies b=-9

Therefore the equation for function g(x) is:

g(x)=x^2-9

<h3><u>Part 4</u></h3>

The length AC is the difference between the x-values of points A and C.

\implies x_A-x_C=3-(-3)=6

Point B is the y-intercept of g(x), so when x = 0:

\implies g(0)=(0)^2-9=-9

Therefore, B = (0, -9).

The length OB is the difference between the y-values of the origin and point B.

\implies y_O-y_B=0-(-9)=9

Therefore, AC = 6 units and OB = 9 units

3 0
2 years ago
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Step-by-step explanation:

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4 years ago
Can somebody anybody help me with questions 10-16 PLEASE
gtnhenbr [62]

Answer:

Sure! To help you here is a really good resource that you can use to answer these questions with work being show!

6 0
3 years ago
a diesel train left berlin and traveled north at an average speed of 25 km/h. A cattle train left at the same time and traveled
max2010maxim [7]

Answer:

10 hours

Step-by-step explanation:

Let N represent the distance the train heading north has traveled

Let S\\ represent the distance the train heading south has traveled

Let t represent the number of hours that has passed

N=25t\\S=35t

600=N+S

600=25t+35t\\600=60t\\t=10

6 0
3 years ago
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