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azamat
1 year ago
11

Please solve quickly ​

Mathematics
2 answers:
masya89 [10]1 year ago
5 0

Answer:

13.8 sq.cm

Step-by-step explanation:

Area of shaded region = area of square - area of 4 quater circles

(4 quater circles=1 circle)

= area of square - area of one circle

= s^2 - πr^2

= 8×8 - 3.14 × 4×4 (<em>r </em><em>=</em><em> </em><em>4</em><em>c</em><em>m</em><em> </em><em>because</em><em> </em><em>radius </em><em>is </em><em>half </em><em>of </em><em>the </em><em>side </em><em>of </em><em>square</em><em>)</em>

= 64 - 3.14 ×16

= 64 - 50.24

= 13.76

Nearest tenth of 13.76 is 13.8

shtirl [24]1 year ago
3 0

Answer:

41.2 cm^2

Step-by-step explanation:

Square area = 8x8 = 64 cm^2

The sum of the 4 white areas is a circle of radius r = 4cm

The area of the circle is \pi r^{2} = 16\pi = 22.8 cm^2

The yellow region is the difference = 64 - 22.8 = 41.2 cm^2

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3 years ago
Choose all the fractions that are in simplest form. <br> 9/14 7/21 6/15 18/23 8/15
Rufina [12.5K]

Answer:

9/14 ; 18/23 ; 8/15

Step-by-step explanation:

7/21 = 1/3

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7 0
2 years ago
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PLS HELP ASAP!!! In the following diagram DE | FG and KL | FG what is the measure of angle X
myrzilka [38]

Answer:

<x=28 degrees

Step-by-step explanation:

Since we know line KL and FG are perpendicular, and DE and FG are parallel, then KL and DE must also be perpendicular.

Angles GCA, JCB, IAE, and CAD are all the same angle. Angles IAD, EAC, GCJ, and ACB are all the same angle. Since DE and KL are perpendicular, then angles KAD, KAE, EAL, and DAL all are 90 degrees, or right angles.

Because we know all this, we can take the angle of KAD, 90 degrees, and subtract 62 from it to find the angle of IAD. This is 28 degrees. Since angle IAD is equal to angle GCJ, which is also angle x, angle x is 28 degrees.

Hope this helps! Please mark me Brainliest!

6 0
2 years ago
How the heck do you solve these type of problems?
chubhunter [2.5K]
Do the math the same way you would if all the other variables were numbers. For linear equations such as these, you can
• subtract one side of the equation, so you get an equation equal to zero.
• factor out the variable of interest
• subtract all terms that don't have the variable as a factor
• divide by the coefficient of the variable.

19. 2xy - x - 7 = 0 . . . . subract the right side
  x(2y-1) -7 = 0 . . . . factor out x
  x(2y -1) = 7 . . . . subtract the term(s) not containing x. Subtract -7 here.
  x = 7/(2y -1) . . . . divide by the coefficient of x

20. Usually for these, you would eliminate fractions first. (You don't have to, but it does simplify things a bit.)
  2d + f = 24 . . . . multiply the equation by 4 to eliminate fractions
  f = 24 - 2d . . . . subtract the term not involving f

21. We can go back to the above sequence of steps here, if you like.
  3(2j -k) -108 = 0 . . . . subtract the right side
  6j -3k -108 = 0 . . . . separate the j terms from the others (eliminate parentheses using the distributive property)
  6j = 108 + 3k . . . . add the opposite of the non-j terms
  j = 108/6 + 3k/6 . . . . divide by the coefficient of j
  j = 18 + k/2 . . . . simplify

22. "solve for" variable not specified.
  t = (3.5s -42)/4
  s = (4t+42)/3.5
In both cases, the 3.5 can be replaced by 7/2 and the fraction simplified.
  t = (7/8)(s-12)
  s = 12 + (8/7)t
6 0
3 years ago
HeLP ASAP <br> worth many points<br> No random answer or get reported<br><br> Answer ALL THREE
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Ok i) The equation for a slope is y= mx + c where m is the gradient and c the y-intercept. Ok so the gradient is the y rise / x run. You have selected -2 to 4. The rise is -2 and the run is 4. -2 / 4 = -0.5. So y = -0.5x - 2

ii) (0, -2)

iii) I think this one number i). Ill do i) here, -0.5

7 0
2 years ago
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