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2 years ago

PLEASE HELP I WILL NAME YOU THE BRAINIEST

Mathematics

2 answers:

tino4ka555 [31]2 years ago

8 0

2 x 1/6 = 2/6 which can be reduced to 1/3
4 x 3/8 = 1 and 4/8 which can again be reduced to 1 and 1/2

problem 2 - 3/4

problem 3 - 2 (whole number)

Aleks04 [339]2 years ago

7 0

Answer:

(1)

A : 1/3

B: 3/2

C: 3/5

(2.) : 3/4

(3): 2

Step-by-step explanation:

You might be interested in

For your birthday, you want to take a group of friends to an indoor trampoline

butalik [34]

Answer:

For Skyhigh : 40 friends

For Jump it up : 90 friends

Step-by-step explanation:

Given that :

Maximum spending = $250

SKY HIGH FEES :

Party set up fee = $50 ; Amount paid per person = $2

JUMP IT UP FEES :

Party set up fee = $70 ; Amount paid per person = $2

THEREFORE, the inequality statement to obtain the number of friends for eack trampoline center goes thus:

Party setup fee + Number of persons * fee per person ≤ maximum spending

SKY HIGH:

50 + 5x ≤ 250

5x ≤ 250 - 50

5x ≤ 200

x ≤ 200/5

x ≤ 40

Hence,

Skyhigh can accommodate 90 friends Given the conditions

JUMP IT UP:

70 + 2x ≤ 250

2x ≤ 250 - 70

2x ≤ 180

x ≤ 180/2

x ≤ 90

Jump it up can accommodate up to 90 friends Given the conditions.

4 0

3 years ago

What is the result when 2/5x + 1 1/4 is subtracted 2/38x - 4 1/9? (NEED ASAP)

Katyanochek1 [597]

Answer:

33 x/ 95 − 103/ 36

Step-by-step explanation: i had too many steps and i cant type them all out.

This answer is only correct if you are talking about subtracting.

7 0

3 years ago

Please show me how u got theses Answer

musickatia [10]

Answer:

7 x 7 x 7= 49 x 7= 343

3 x 3 x 3 x 3= 9 x 3 x 3= 27 x 3= 81

3 0

2 years ago

Three tanks are capable of holding 361,841, and 901 of the greatest vessel winch can be used to fill each one of them on exact n

daser333 [38]

Answer:

Tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

Step-by-step explanation:

Three tanks are capable of holding $361,841,901$

To find which tank can be used to fill each one of them an exact number of time, find $HCF(361,841,901)$

$361=19^2\\841=29^2\\901=17(53)$

Therefore,

$HCF(361,841,901)=1$

So, tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

6 0

3 years ago

Suppose that one-way commute times in a particular city are normally distributed with a mean of 15.43 minutes and a standard dev

vovikov84 [41]

Answer:

Yes, a commute time between 10 and 11.8 minutes would be unusual.

Step-by-step explanation:

A probability is said to be unusual if it is lower than 5% of higher than 95%.

We use the normal probability distribution to solve this question.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 15.43, \sigma = 2.142$

Would it be unusual for a commute time to be between 10 and 11.8 minutes?

The first step to solve this problem is finding the probability that the commute time is between 10 and 11.8 minutes. This is the pvalue of Z when $X = 11.8$ subtracted by the pvalue of Z when X = 10. So