Why can a problem with extra information be difficult to solve?

According to the U.S. Census Bureau, the prob ability that a randomly selected household speaks only English at home is 0.81. Th

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that according to the U.S. Census Bureau, the prob ability that a randomly selected household speaks only English at home is 0.81.

The probability that a randomly selected household speaks only Spanish at home is 0.12.

(a) the probability that a randomly selected household speaks only English or only Spanish at home

= 0.81+0.12 = 0.93

(since these two are disjoint sets)

(b) the probability that a randomly selected household speaks a language other than only English or only Spanish at home

= 1-0.93= 0.07 (remaining)

(c) the probability that a randomly selected household speaks a language other than only English at home

=1-0.81=0.19

(d) Can the probability that a randomly selected household speaks only Polish at home equal 0.08? Why or why not?

Polish alone can never exceed 1-(0.81+0.12) i.e. 0.70

At most it can take values as 0.7 only

So no is the answer.

4 0

2 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago

Which is equivalent to sin-1(–0.4)?

Gekata [30.6K]

–2.50 –0.60 –0.41 –0.39

5 0

2 years ago

Read 2 more answers

Solve the equation for the unkown variable<br> 1) -1/x=-7/2+2/x

lakkis [162]

Hope this might help

6 0

2 years ago

Read 2 more answers

The radius of circle L is 16 cm.

timurjin [86]

The anwser is for the question tht u are looking for is no other then the first anwser A!!!

6 0

3 years ago