The statements that I agree with, with respect to a parallelogram are:
- A parallelogram has six sides.
- Opposite sides of a parallelogram are parallel.
- All angles of a parallelogram have the same measure.
- All sides of a parallelogram have the same length.
<h3>What is a
parallelogram?</h3>
A parallelogram can be described as the quadrilateral that do contains two pairs with respect to their parallel sides.
It should be noted that the sides that can be found in the parallelogram are usually of the same length and there the sides that can be attributed to a parallelogram is usually 6.
Therefore, the option 1,2,4,5 are correct.
Learn more about parallelogram at:
brainly.com/question/970600
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I hope this helps you
-15+6= -9
-9+6= -3
-3+6=3
add 6
Answer:
0.6154 = 61.54% probability that the student is an undergraduate
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Foreign
Event B: Undergraduate.
There are four times as many undergraduates as graduate students
So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.
Probability the student is foreign:
10% of 80%
25% of 20%. So
![P(A) = 0.1*0.8 + 0.25*0.2 = 0.13](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.1%2A0.8%20%2B%200.25%2A0.2%20%3D%200.13)
Probability that a student is foreign and undergraduate:
10% of 80%. So
![P(A \cap B) = 0.1*0.8 = 0.08](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.1%2A0.8%20%3D%200.08)
What is the probability that the student is an undergraduate?
![P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20%5Cfrac%7B0.08%7D%7B0.13%7D%20%3D%200.6154)
0.6154 = 61.54% probability that the student is an undergraduate