Answer:
A. 4 CPUs and 6 megabyte cache memory
B. 1.3157 x10^-9 nanoseconds
Explanation:
The Intel core i5 7500 is a seventh generation central processing unit with a 4 CPU core and a 6 megabyte cache memory. It executes task at a clock cycle of 5 clock cycle at a speed of 3.8 GHz.
The relationship between frequency and clock cycle is,
Clock cycle = 1 / ( frequent).
So, One clock cycle = 1 / 3.8 GHz
= 0.3 x10^-9
For five clock cycles = 5 x 0.3 x10^-9
= 1.3157 x10^-9 nanoseconds.
Answer:
7 bytes
Explanation:
<u>2 Address Instruction</u>
The 2 address instruction consist 3 components in the format.
One is opcode,other two are addresses of destination and source.
<u>Example-</u>
load b,c | Opcode destination address,source address
add a,d | Opcode destination address,source address
sub c,f | Opcode destination address,source address
Opcode consists of 1 bytes whereas destination address and source address consist of 3 bytes each.
(1+3+3) bytes=7 bytes
Answer:
computers
Explanation:
it is because other remaining are not able to access network
Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number
<h3>Writting in C++ code:</h3>
<em />
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>bool isPrime(int n){</em>
<em> for(int i = 2; i < n/2; i++){</em>
<em> if(n%i == 0){</em>
<em> return false;</em>
<em> }</em>
<em> }</em>
<em> return true;</em>
<em>}</em>
<em>int findPrimeSum(int n){</em>
<em> int sumVal = 0;</em>
<em> for(float i = 2; i <= n; i++){</em>
<em> if(isPrime(i))</em>
<em> sumVal += i;</em>
<em> }</em>
<em> return sumVal;</em>
<em>}</em>
<em>int main(){</em>
<em> int n = 15;</em>
<em> cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>
<em> return 0;</em>
<em>}</em>
See more about C++ code at brainly.com/question/19705654
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Network Interface Controller