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3 years ago

True or False: Unity can apply multiple textures to a single object or terrain

Computers and Technology

1 answer:

MaRussiya [10]3 years ago

3 0

This is very true unity is what u said and it is the definition of this

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Write a for loop that computes the following sum: 5+10+15+20+...+485+490+495+500. The sum should be placed in a variable sum tha

Strike441 [17]

Answer:

public class num9 {

public static void main(String[] args) {

int sum =0;

int num =5;

for(num =5; num<=500; num+=5){

System.out.println(num);

sum +=num;

}

System.out.println(sum);

}

Explanation:

Declare and initialize the variables sum and num
Use a for loop with the condition for(num =5; num<=500; num+=5) Since the loop will increment by 5 and run from 5 to 500
Within the loop, add num to sum at each iteration
Print all elements on seperate lines
Outside the loop, print the final value of sum

Create a for loop

6 0

3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago

What is it called when there are an equal number of characters on either side of the horizontal center of the page?

Naddika [18.5K]

Answer: the term is known as Align Justified

Explanation:

In typesetting and page layout, alignment or range is the setting of text flow or image placement relative to a page, column, table cell, or tab. The type alignment setting is sometimes referred to as text alignment, text justification, or type justification.

5 0

2 years ago

Which blog had legal content and is written mostly by lawyers

Svetradugi [14.3K]

Is it asking for a web site like .edu? or something like that?

6 0

3 years ago

Read 2 more answers

Whats included in ms office 2013 professional?

MrMuchimi

Powerpoint, word document, and excel

3 0

3 years ago