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Scrat [10]
2 years ago
10

Maria and Nate graphed lines on a coordinate plane. Maria's line is represented by the equation y = -5/6x +8. Nate's line is per

pendicular to Maria's line. Which of the following could be an equation for Nate's line?
a 5x-6y=15
b 5x+6y=15
c 6x-5y=15
d 6x+5y=15
Mathematics
1 answer:
eduard2 years ago
3 0

Answer:

c)   6x - 5y = 15

Step-by-step explanation:

Slope-intercept form of a linear equation:  y=mx+b

(where m is the slope and b is the y-intercept)

Maria's line:  y=-\dfrac{5}{6}x+8

Therefore, the slope of Maria's line is -\frac{5}{6}

If two lines are perpendicular to each other, the product of their slopes will be -1.

Therefore, the slope of Nate's line (m) is:

\begin{aligned}\implies m \times -\dfrac{5}{6} &=-1\\m & =\dfrac{6}{5}\end{aligned}

Therefore, the linear equation of Nate's line is:

y=\dfrac{6}{5}x+b\quad\textsf{(where b is some constant)}

Rearranging this to standard form:

\implies y=\dfrac{6}{5}x+b

\implies 5y=6x+5b

\implies 6x-5y=-5b

Therefore, <u>option c</u> could be an equation for Nate's line.

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got u

Step-by-step explanation:

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3 years ago
Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
Elden [556K]

Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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3 years ago
Simplify. Consider all cases.<br> |14−(x−6)|<br> |14−(6-x)|
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Answer:

8+x if x > -8

8 if x = 0

-8-x if x < -8

Step-by-step explanation:

|14−(6-x)|

|14−6+x|

|8+x|

8+x if x > -8

8 if x = 0

-8-x if x < -8

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8 0
2 years ago
Read 2 more answers
Solve the simultaneous equation 2p - 3q = 4, 3p + 2q = 9. <br>b. if 223= 87 find x<br>​
wolverine [178]

Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

2p - 3q = 4 ...................... 1 * 3

3p + 2q = 9 ..................... 2 * 2

Multiplying equation 1 by 3 and 3 by 2:

6p - 9q = 12

6p + 4q = 18

Subtracting both equation

-9q-4q = 12-18

-13q = -6

q = -6/-13

q = 6/13

Substituting q = 6/13 into equation 2

2p - 3(6/13) = 4

2p - 18/13 = 4

2p = 4+18/13

2p = (52+18)/13

2p = 70/13

p = 70/26

p = 35/13

<em>Hence p = 35/13 and q = 6/13</em>

<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

223ₓ = 2*x² + 2*x¹ + 3*x⁰

223ₓ  = 2x²+2x+3

​

Substituting back into the equation, 2x²+2x+3 = 87

2x²+2x+3-87 = 0

2x²+2x-84 = 0

x²+x-42 = 0

On factorizing:

(x²+6x)-(7x-42) = 0

x(x+6)-7(x+6) = 0

(x+6)(x-7) = 0

x+6 = 0 and x-7 = 0

x = -6 and 7

<em>Hence the value of x is 7 (neglecting the negative value)</em>

5 0
3 years ago
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