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3 years ago

What proportion shows the relationship among the whole the part and the percent in a percent problem

Mathematics

1 answer:

PolarNik [594]3 years ago

6 0

Part/whole = %/100 like if it was 10 % of 20, x/20=10/100 or 2is what percent of 20 would be 2/20=%/100

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A total of 5000 is invested part at 10% and the remainder at 15%. How much is invested at Each rate if the annual interest is $6

vekshin1

Answer:Let the amount invested in each be

A and B

A+B=5000

0.1A+0.15B=630

0.1(5000-B)+0.15B=630

500-0.1B+0.15B=630

0.05B=130

B=2600

A=2400

Step-by-step explanation:

3 0

3 years ago

what you know about the toy made with 27 small cubes to find the relationship between number of cubes on each edge and the total

goldenfox [79]

Answer:

adding

Step-by-step explanation:

adding each numbers on each edge will give a total of the number cubes

7 0

3 years ago

Will give correct answer brainliest

Helga [31]

Answer:

can you please type it cause I can't see I help

6 0

3 years ago

The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $620

nikdorinn [45]

Answer:

Step-by-step explanation:

Let x represent the number of units of games sold.

The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $6200. It means that the total variable cost for x units would be

0.9 × x = 0.9x

The inventor sells each game for $1.69. This means that the total revenue from x units of games sold would be

1.69 × x = 1.69x

The total cost for a business is the sum of the variable cost and the fixed costs. Therefore, the total cost for the number of games sold would be

C = 6200 + 0.9x

Profit = Revenue - total cost

Therefore,

Profit = 1.69x - (6200 + 0.9x)

= 1.69x - 0.9x - 6200

= 0.79x - 6200

8 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago