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photoshop1234 [79]

2 years ago

15

Calculate the magnitude of the angle ABC from the breeze data

1 answer:

Anna71 [15]2 years ago

6 0

Answer:

∠ ABC = 67°

Step-by-step explanation:

the angle between a tangent and a chord is equal to the angle in the opposite segment, that is

∠ ABC = ∠EAC = 67°

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Someone please help

kogti [31]

Answer:

I'm not 100% but I think it could be x4 and then +5?

Step-by-step explanation:

5 0

3 years ago

Two cars are traveling in the same direction. The first car is going 40 mi/h and the second car is going 55 mi/h. The first car

dexar [7]

Answer:

The equation you are asking for is

40*(t+3) = 55*t,

where t is the time counted after the second car started.

The equation says that the distance covered by each car from the starting point to the catching point is the same for both cars.

Step-by-step explanation:

7 0

3 years ago

Justin is redoing his bathroom floor with tiles measuring 5in. By 14 in. The floor has an area of 8,500 square inches. What is t

ch4aika [34]

<h3>Answer:</h3>

He will need at least 122 tiles

<h3>Step-by-step explanation:</h3>

Get the area of the tiles

5*14= 70 square inches per tile

Divide the floor area by the tile area

8,500/70

121.428571

Round up

122

4 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

6/42 = n/7 N=?<br> I need to find what the numerator is.

PSYCHO15rus [73]

6/42 = n/7
Multiply by 7.
42/42 = n.
n = 1.
numerator = 42.

7 0

2 years ago