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Liono4ka [1.6K]
3 years ago
9

You purchased a rare painting for $150 that is increasing in value by 3% annually. How many years will it take until it is doubl

ed in value? Round to the nearest whole year
Mathematics
1 answer:
Ahat [919]3 years ago
6 0

Answer:

23 years.

Step-by-step explanation:

It is given that the initial price of painting is $150 and its values increasing by 3% annually.

We need to find how many years will it take until it is doubled in value.

The value of painting after t years is given by

y=150(1+0.03)^t

y=150(1.03)^t

The value of painting after double is 300. Substitute y=300.

300=150(1.03)^t

Divide both sides by 150.

2=(1.03)^t

Taking log both sides.

\log 2=\log (1.03)^t

\log 2=t\log (1.03)

t=\dfrac{\log 2}{\log (1.03)}

t=23.44977

t\approx 23

Therefore, the required number of years is 23.

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Is 1/4 greater than, less than or equal to 2/3<br>​
Romashka-Z-Leto [24]

Answer:

Less than

Step-by-step explanation:

1/4 = 0.25 and 2/3 is approximately 0.67 so 1/4 is less than 2/3

8 0
3 years ago
Read 2 more answers
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
Please help me with this it's my last question on my homework :)
Levart [38]
The answer your looking for is 60ft
5 0
3 years ago
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F. If you add § + ģ + , the sum is g. If you add 3 + 2,<br> what is the sum?
inna [77]

Answer:

g. 3+2 =5

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5 0
3 years ago
G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d
____ [38]

By definition of covariance,


\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]


\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]


We have


\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]

=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


\mathbb E[aX-b]=a\mathbb E[X]-b


\mathbb E[cY-d]=c\mathbb E[Y]-d


\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


Putting everything together, we find the covariance reduces to


\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)


as desired.

5 0
3 years ago
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