Planning, designing, gathering data, analyzing, creating relevant interpretations, and publishing the research findings are all statistical approaches that go into conducting a study.
The statistical analysis lends meaning to the abstract numbers, giving the data some life. Only when appropriate statistical tests are applied will the results and inferences be accurate. Science's field of statistics deals with gathering, organizing, analyzing, and extrapolating data from samples to the entire population. This necessitates the use of an acceptable statistical test, an adequate study design, and an appropriate study sample selection. However, if we want additional information about these, a consulting company may be able to assist us. we will benefit more from Silver Lake Consulting for our project.
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Answer:
-7 7/15
Step-by-step explanation:
-11 2/3 -(-4 1/5) = -11 2/3 + 4 1/5. Now, we need to find the LCM of 3 and 5. The LCM of 3 and 5 is 15 because 15 is the lowest number that can divide both 3 and 5 separately and both results will still be whole numbers.
Now, we have -11 10/15 + 4 3/15.
-11 10/15 + 4 3/15 = -7 7/15.
9.70(1.5) = 14.55 ; Maureen's hourly overtime rate is $14.55
Given :
An expression (cos 6m)(cos 2m) .
To Find :
We need to express it in terms as sum or difference.
Solution :
We know,
cos( A + B ) = cosA cos B - sin A sin B
cos( A - B ) = cosA cos B + sin A sin B
Adding both the equations we get :
2cos A cos B = cos( A + B) + cos( A - B )
or
cos A cos B = cos( A + B) + cos( A - B )/2
Putting value of A = 6m and B = 2m in above equation, we get :
(cos 6m)(cos 2m) = cos( 6m + 2m ) + cos( 6m - 2m )/2
(cos 6m)(cos 2m) = cos(8m) + cos(4m)/2
Hence, this is the required solution.
Step-by-step explanation:
Since we are not told what to look for, we can as well look for the value of x, m∠SQT and m∠RQS
Given
m∠RQS=(4x-20)°
m∠SQT=(3x+14)°
m∠RQT=155°
The addition postulate is true
m∠RQT= m∠RQS + m∠SQT
Substitute the given parameters into the formula
155 = 4x-20+3x+14
155 = 7x-6
7x = 155+6
7x = 161
x = 161/7
x = 23
Solve for m∠RQS
m∠RQS = 4x-20
m∠RQS = 4(23)-20
m∠RQS = 92-20
m∠RQS = 72°
Solve for m∠SQT
m∠SQT = 3x+14
m∠SQT = 3(23)+14
m∠SQT = 69+14
m∠SQT = 83°
