Median as there is an outlier (anomaly)
I would need to see the box and whisker plot to answer this question.
Answer:
The graph of the function rule will be a line segment connecting (0,2) and (40,22) as shown in the graph below.
Step-by-step explanation:
The graph of the function rule will be a line segment connecting (0,2) and (40,22) as shown in the graph below.
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
3x+8=5x-1
3x-5x=-1-8
-2x=-9
x=4,5
AM=3x4,5+8=21,5
MB=5x4,5-1=21,5
AB=AM+MB
AB=21,5+21,5=43
