Answer:
y²/25+x²/4=1
Step-by-step explanation:
The equation for an ellipse is either categorized as
x²/c² + y²/d² = 1 . In such an equation, the vertices on the x axis are categorized by (±c,0) and the vertices on the y axis are (0, ±d)
In the ellipse shown, the vertices/endpoints on the x axis are (-2,0) and (2,0). This means that c is equal to 2. Similarly, on the y axis, the endpoints are (5,0) and (-5,0), so d=5.
Our equation is therefore x²/2²+y²/5²=1 = x²/4+y²/25=1
Our answer is therefore the fourth option, or
y²/25+x²/4=1
Answer:C
Step-by-step explanation:Just did it on apex and got it correct ✋:)
I don’t know if I’m wrong but Yeah I Think It’s C
Answer:
f(x) = -5x + 4
Domain refers to the values of x that would result to a defined value of y. Since the given f(x) is a linear function, then all the values of x would give a corresponding value of y. So, the domain of f(x)=-5x+4 are all real numbers.
Or, plot the given equation to check.
The graph of f(x)=-5x+4 is shown below.
Since the graph is a straight line and can be extended continuously on both ends, this indicates that every values of x, there is a corresponding value of y.
Hence, the domain of the given function are all real numbers.Step-by-step explanation:
Answer:
Since the focus is at (-6,-11) and the directrix is at y=9:
The vertex is halfway between the focus and the directrix, so the vertex is at (-6,-1). (Draw this on graph paper if that doesn't make sense.)
The general form (conics form) of a parabola: 4p(y-k)=(x-h)^2 (vertex is (h,k) and "p" is the distance between the focus and vertex (or between vertex and directrix)).
(h,k) = (-6,-1)
p = 10 (distance between focus and vertex), so 4p = 40.
Therefore:
40(y+1)=(x+6)^2
Or if you need to rearrange to "vertex form": y=(1/40)(x+6)^2 - 1
Step-by-step explanation:
