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castortr0y [4]
3 years ago
11

A runner ran a 400 m race in 1 min 35 sec. Calculate his average speed in m/sec.

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0

Step-by-step explanation:

distance = 400m

time taken = 1 min 35 sec = 95 sec

average speed = 400m / 95 sec = 4=2105 m/ sec

Fed [463]3 years ago
7 0

Answer:

4.21 m / sec.

Step-by-step explanation:

1 min 35 sec.

= 60 + 35

= 95 sec.

So average speed = 400/95

= 4.21 m / sec.

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Find the volume of the cube.
iren [92.7K]

Answer:

60 cm & 60 mL

Hope this helps! Let me know if this is right or not.

8 0
3 years ago
What is the ratio of 3/20
Sveta_85 [38]
The ratio of 3/20 is 3:20
5 0
3 years ago
What is the length of side BC? Round the answer to the nearest tenth.
Nostrana [21]

Answer:

The length of side BC is 2.8 units

Step-by-step explanation:

* Lets revise how to find the distance between two points

- If there are two points their coordinates are (x1 , y1) and (x2 , y2),

 then we can find the distance between them by this rule:

 d = √[(x2 - x1)² + (y2 - y1)²]

- Now lets solve the problem

∵ B = (3 , 3)

∵ C = (5 , 1)

- To find the length of BC use the rule of the distance above

- Let point B is (x1 , y1) and point C is (x2 , y2)

∵ x1 = 3 and x2 = 5

∵ y1 = 3 and y2 = 1

∴ BC = √[(5 - 3)² + (1 - 3)²]

∴ BC = √[(2)² + (-2)²]

∴ BC = √[4 + 4] = √8 = 2.8 units

* The length of side BC is 2.8 units

7 0
3 years ago
Read 2 more answers
The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a
mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let <em>X</em> = the waiting time for the bus at the parking lot.

The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.

The probability density function of <em>X</em> is given as follows:

f_{X}(x)=\frac{1}{b-a};\ a

(a)

The standard deviation of a Uniformly distributed random variable is given by:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

Compute the standard deviation of the random variable <em>X</em> as follows:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

      =\sqrt{\frac{(15-0)^{2}}{12}}

      =\sqrt{\frac{225}{12}}

      =\sqrt{18.75}\\=4.33

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

X=2\times SD=2\times4.33=8.66

Compute the value of P (X > 8.66) as follows:

P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\

                    =\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\

                    =\frac{1}{15}\times |x|^{15}_{8.66}\\

                    =\frac{15-8.66}{15}\\

                    =0.4227

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

4 0
3 years ago
Find the next two !!!
melomori [17]

It's adding 3 and subtracting 2 every time.

This means the next two terms would be +3 and -2 since the last one was -2.

The next term = 4+3=7

The next next term = 7-2=5

5 0
3 years ago
Read 2 more answers
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