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Dmitrij [34]
2 years ago
9

I might mark brainliest I just need help

Mathematics
1 answer:
Artemon [7]2 years ago
8 0

Answer:

i think you have to measure your diagram with a protector to find the angles

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Find two positive numbers so that twice their sum equals their product and one number is 10 times the other number. Enter the sm
Softa [21]

Answer:

Step-by-step explanation:

We'll call the 2 numbers x and y. Starting with the last part of that first sentence "one number is 10 times the other number" can be written, in algebraic form:

y = 10x

Now on to the first statement about the numbers: "twice their sum" is 2(x + y) and "equals their product" is = xy. Putting that all together:

2(x + y) = xy and we know that y = 10x so

2(x + 10x) = x(10x) and

2(11x)=10x^2 and

10x^2-22x=0 and

x(10x - 22) = 0 so

x = 0 or 10x - 22 = 0 which makes

x equal to \frac{22}{10}=2.2

So x = 2.2 and y = 22.

7 0
2 years ago
Given that a and b are legs of a right triangle and c is the hypotenuse. Solve for the missing length using the Pythagorean Theo
Levart [38]

Answer:

D

Step-by-step explanation:

a^2+b^2=c^2

7^2+9^2=C^2

49+81=c^2

\sqrt{49+81}=c

\sqrt{130}=c

3 0
2 years ago
Find S12 for geometric series: (-7.5) + 15 + (-30) + ...
kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

5 0
3 years ago
What is the perpendicular gradient for the equation of a straight line <br>y=-1/2x+c​
satela [25.4K]

Answer:

The perpendicular gradient is 2x

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2 years ago
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Factor this expression.
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Answer:

D

Step-by-step explanation:

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