From the figure, the dilation constant from ΔABC to ΔDEF is
QD/QA = 8/4 = 2
Test QB = QE:
We should have
QB = (1/2) QE
The statement is incorrect.
Test QC = CF:
We should have
QC = (1/2) QF, or QC = CF
The statement is correct.
Test DE = 2AB:
We should have
AB = (1/2)DE, or 2AB = DE.
The statement is correct.
Test AC = EF:
We should have
AC = (1/2)DF
The statement is incorrect.
We should also have
BC = (1/2)EF
Therefore, if BC = 2.25, then
EF = 2*BC = 2*2.25 = 4.5.
Answer:
QC = CF
DE = 2AB
EF = 4.50
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em><em>5</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
Answer:
B
Step-by-step explanation:
To solve this, we use ratio.
Firstly, we need to know the number of hours traveled. The total number of hours traveled = x+y
Ratio of this used by high speed train = x/(x +y).
Total distance traveled before they meet = [x/(x + y)] × z
For low speed train = [y/(x + y)] × z.
The difference would be distance by high speed train - distance by low speed train.
= z [ (x - y)/x + y)]
Answer:
The upper 20% of the weighs are weights of at least X, which is
, in which
is the standard deviation of all weights and
is the mean.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Upper 20% of weights:
The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then



The upper 20% of the weighs are weights of at least X, which is
, in which
is the standard deviation of all weights and
is the mean.
0.8 is the answer I hope this helps if you don’t want it decimal form here’s exact from 4/5