Answer:
1- 16x-12
2- 6(6x-1)
3. -qx+24x-18
Step-by-step explanation:
Hope this help
Have a nice day
The firefighters would not be able to reach the cat because the ladder is only 35 cm tall and the cat is 39m up (I HOPE THIS ACTUALLY HELP IF IT DOES NOT I HOPE SOMEONE CAN HELP YOU)
Answer:
<h3>k = 10</h3>
Step-by-step explanation:
Given the equation;
![\dfrac{k}{100} = \dfrac{1}{10}](https://tex.z-dn.net/?f=%5Cdfrac%7Bk%7D%7B100%7D%20%3D%20%5Cdfrac%7B1%7D%7B10%7D)
We are to find the value of k.
Cross multiply;
![\dfrac{k}{100} = \dfrac{1}{10} \\10 \times k = 100 \times 1\\10k = 100\\](https://tex.z-dn.net/?f=%5Cdfrac%7Bk%7D%7B100%7D%20%3D%20%5Cdfrac%7B1%7D%7B10%7D%20%5C%5C10%20%5Ctimes%20k%20%3D%20100%20%5Ctimes%201%5C%5C10k%20%3D%20100%5C%5C)
Divide both sides by 10
![10k/10 = 100/10\\k = 10](https://tex.z-dn.net/?f=10k%2F10%20%3D%20100%2F10%5C%5Ck%20%3D%2010)
Hence the value of k is 10
A negative correlation: when the number of years increase the value of the car decrease.
Answer: 38.41 minutes
Step-by-step explanation:
The standard error for the difference in means is given by :-
![SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B%5Csigma_1%5E2%7D%7Bn_1%7D%2B%5Cdfrac%7B%5Csigma%5E2_2%7D%7Bn_2%7D%7D)
where ,
= Standard deviation for sample 1.
= Size of sample 1.
= Standard deviation for sample 2.
= Size of sample 2.
Let the sample of Latino name is first and non -Latino is second.
As per given , we have
![n_1=9](https://tex.z-dn.net/?f=n_1%3D9)
![n_2=14](https://tex.z-dn.net/?f=n_2%3D14)
The standard error for the difference in means will be :
![SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B%2882%29%5E2%7D%7B9%7D%2B%5Cdfrac%7B%28101%29%5E2%7D%7B14%7D%7D)
![SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B6724%7D%7B9%7D%2B%5Cdfrac%7B10201%7D%7B14%7D%7D)
![SE.=\sqrt{747.111111111+728.642857143}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B747.111111111%2B728.642857143%7D)
![SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B1475.75396825%7D%3D38.4155433158%5Capprox38.41)
Hence, the standard error for the difference in means =38.41 minutes