Question

The Northwest High School senior class decided to host a raffle to raise money for their senior trip. They charged $2 for each student raffle ticket and $5 for each adult raffle ticket and they raised $2,686 from ticket sales. If adults bought 3 times as many tickets as students, how many tickets did the senior class sell?
2x + 5y = 2,686
y = 3x

Northwest High School’s senior class sold ___ raffle tickets.

Answer 1

Let $x$ be the tickets that the adults bought, and$y$ be the tickets that children bought.
From the problem we have the system of linear equations:
$\left \{ {{2x+5y=2686} \atop {y=3x}} \right.$

The first thing we are going to do to solve our system, is replacing equation (2) in equation (1), and  then, solve for $x$
$2x+5y=2686$
$2x+5(3x)=2686$
$2x+15x=2686$
$17x=2686$
$x= \frac{2686}{17}$
$x=158$

Now that we have the number of tickets that the adults bought, lets replace that value in equation (2):
$y=3x$
$y=3(158)$
$y=474$

Last but not least, to find the total number of tickets, we are going to add $x$ and $y$:
$158+474=632$

We can conclude that Northwest High School's senior class sold 632 raffle tickets.

Answer 2

Answer:

the senior class sold 632 raffle tickets.

Step-by-step explanation:

got it right on edge 2020