By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
To learn more on quadratic equations: brainly.com/question/1863222
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Answer:
Step-by-step explanation:
Negative three is less than (<) negative one, so any statement saying otherwise is incorrect. Correct choices are ...
-3 ≤ -1
-3 < -1
Answer:
x > -6
Step-by-step explanation:
X - 9 > -15
x > -6
Answer:
SAS theorem
Step-by-step explanation:
Given
Required
Which theorem shows △ABE ≅ △CDE.
From the question, we understand that:
AC and BD intersects at E.
This implies that:
and
So, the congruent sides and angles of △ABE and △CDE are:
---- S
---- A
or --- S
<em>Hence, the theorem that compares both triangles is the SAS theorem</em>
<span>3(x+4)^2-24=0
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<span>3(x+4)^2 = 24
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<span>(x+4)^2 = 24/3
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<span>(x+4)^2 = 8
</span><span>
</span><span>(x+4)² = (2√2)² ⇒ x+4 = 2√2 ⇒ x = 2√2 - 4
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