Is this from k12? i am a k12 student, and the answer should be 2.2 units but I could be wrong.
The largest number of Bird in the tree could be 14
Step-by-step explanation:
A:B:C
2:3
6:7
12:18:42
I think...
Total distance 5 km; at 5km / 0.65 h =
Second part distance: x; at 6 km/h, during t2
First part distance: 5 - x; at 8.75 km/h, during t1
V = d/t ⇒ t = d/V
t2 = x/6
t1=[5-x]/8.75
t2 + t1 = 0.65
x/6 + [5-x]/8.75 = 0.65
x/6 + 5/8.75 - x/8.75 = 13/20
x/6 - x/8.75 = 13/20 - 5/8.75
x/6 - 4x/35 =13/20 - 20/35
35x - 24x = (35*6)(35*13 - 20*20)/(20*35)
11 x = 16.5
x = 16.5/11 = 1.5 km
Answer:
a) 
b) 
c) 
d) 
e) The intersection between the set A and B is the element c so then we have this:

Step-by-step explanation:
We have the following space provided:
![S= [a,b,c,d,e]](https://tex.z-dn.net/?f=%20S%3D%20%5Ba%2Cb%2Cc%2Cd%2Ce%5D)
With the following probabilities:

And we define the following events:
A= [a,b,c], B=[c,d,e]
For this case we can find the individual probabilities for A and B like this:


Determine:
a. P(A)

b. P(B)

c. P(A’)
From definition of complement we have this:

d. P(AUB)
Using the total law of probability we got:

For this case
, so if we replace we got:

e. P(AnB)
The intersection between the set A and B is the element c so then we have this:
