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Nastasia [14]
3 years ago
12

The midsegment of triangle ABC is LM. What is the length of LM if AC is 26 inches long?

Mathematics
3 answers:
defon3 years ago
8 0
Check the picture below.

Alexandra [31]3 years ago
6 0

13 inches for an easier answer.

you divide 26 with 2 to get the answer (:

QB19
2 years ago
24
QB192 years ago
0 0

24 for apex people fyi

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bixtya [17]

Using an exponential function, it is found that f(5.5) = 19.8.

<h3>What is an exponential function?</h3>

An exponential function is a function in which the growth rate is a percentage, modeled by:

y = ab^x

In which:

  • a is the initial value.
  • b is the rate of change.

f(3.5) = 25 means that:

ab^{3.5} = 25

a = \frac{25}{b^{3.5}}

f(8.5) = 14 means that:

ab^{8.5} = 14

Hence:

\frac{25}{b^{3.5}} \times b^{8.5} = 14

25b^5 = 14

b = \sqrt[5]{\frac{14}{25}}

b = 0.89

a = \frac{25}{0.89^{3.5}} = 37.59

Hence, the function is given by:

y = 37.59(0.89)^x

Then, when x = 5.5:

f(5.5) = 37.59(0.89)^{5.5} = 19.8

More can be learned about exponential functions at brainly.com/question/25537936

7 0
2 years ago
What is the product of 5×10'5​
Oksanka [162]
(if the last five is an exponent, here is the answer)

5 • 10^5
first work on the exponent
5 • 100,000
multiply
500,000
6 0
3 years ago
What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m
Shtirlitz [24]

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg

Thus, the mass of the solid ball of iron is 60.6528 kg

8 0
2 years ago
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