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TiliK225 [7]
2 years ago
8

Simplify each expression by writing the expression without absolute value bars. |x-2| if x>-1

Mathematics
1 answer:
LenaWriter [7]2 years ago
4 0

Answer:

if X is greater than 1 equal negative 1

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A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
Hurry I'm timed hurryryeye
kozerog [31]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>1</u><u>7</u><u>1</u>

Step-by-step explanation:

{x}^{2}  - 3y + x

substitute for x and y:

=  {(14)}^{2}  - 3(13) + 14 \\  = 196 - 39 + 14 \\  = 171

4 0
3 years ago
Read 2 more answers
Which expression is a perfect cube?
Bingel [31]

we know that

A perfect cube is a whole number which is the cube of another whole number or a number is a perfect cube if the cube root of that number is a whole number.

so

<u>case a)</u> 12x^{12} y^{18}

12x^{12} y^{18} = 12(x^{4} y^{6})^{3}

the cube root of 12 is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>case b)</u> 12x^{27} y^{125}

12x^{27} y^{125} = 12(x^{9})^{3}y^{125}

the cube root of 12 is not a whole number

the cube root of y^{125} is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>case c)</u> 64x^{15} y^{18}

64x^{15} y^{18} = (4 x^{5} y^{6})^{3}

therefore

<em><u>The expression is a perfect cube</u></em>

<u>case d)</u> 64x^{27} y^{125}

64x^{27} y^{125} = (4 x^{9})^{3}y^{125}

the cube root of y^{125} is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>the answer is</u>

64x^{15} y^{18}

7 0
4 years ago
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Plz help will mark as brainliest
yan [13]

Answer:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

Exact Form:

x = 2 √ 3 − 2

Decimal Form:

x = 1.46410161 …

7 0
3 years ago
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In the formula for the area of a circle, what gets multiplied by pi
Musya8 [376]

Answer:

r², or the radius squared

Step-by-step explanation:

The formula for the area of a circle is

πr²

So the the radius squared is being multiplied by pi.

6 0
3 years ago
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