Step-by-step explanation:
Let
= mass of the painter
= mass of the scaffold
= mass of the equipment
= tension in the cables
In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of
. The net torque on the scaffold is then

Solving for T,

or
![T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B9%7D%5Bm_sg%281.9%5C%3A%5Ctext%7Bm%7D%29%20%2B%20m_pg%284.2%5C%3A%5Ctext%7Bm%7D%29%5D)

To solve for the the mass of the equipment
, use the value for T into Eqn(1):

Answer:
<u>It</u><u> </u><u>is</u><u> </u><u>1</u><u>7</u><u>1</u>
Step-by-step explanation:

substitute for x and y:

we know that
A perfect cube is a whole number which is the cube of another whole number or a number is a perfect cube if the cube root of that number is a whole number.
so
<u>case a)</u> 

the cube root of
is not a whole number
therefore
<em><u>The expression is not a perfect cube</u></em>
<u>case b)</u> 

the cube root of
is not a whole number
the cube root of
is not a whole number
therefore
<em><u>The expression is not a perfect cube</u></em>
<u>case c)</u> 

therefore
<em><u>The expression is a perfect cube</u></em>
<u>case d)</u> 

the cube root of
is not a whole number
therefore
<em><u>The expression is not a perfect cube</u></em>
<u>the answer is</u>

Answer:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Exact Form:
x
=
2
√
3
−
2
Decimal Form:
x
=
1.46410161
…
Answer:
r², or the radius squared
Step-by-step explanation:
The formula for the area of a circle is
πr²
So the the radius squared is being multiplied by pi.