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elixir [45]
2 years ago
7

DUE SOON PLEASE HELP

Mathematics
1 answer:
9966 [12]2 years ago
7 0

Answer:

9% sry if im wrong

Step-by-step explanation:

Kayla has some colored marbles that are the same size and shape. Use

the information below to determine which is closest to the probability

that Kayla will randomly select a marble that is not red, replace it, then

randomly select a marble that is yellow?

The probability of randomly selecting a red marble is 30%.

The probability of randomly selecting a yellow marble is 13%

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Alex73 [517]

Answer:

c

Step-by-step explanation:

x^{-6}*x^{-5}=x^{(-6)+(-5)}=x^{-11}=\frac{1}{x^{11}}

x^{a}*x^{b}=x^{a+b}\\\\x^{-a}=\frac{1}{x^{a}}

6 0
4 years ago
Help please!!!!! ASAPPPP
r-ruslan [8.4K]

Answer:

the numerator is 31 and the bottom is 8

Step-by-step explanation:

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
Read 2 more answers
Please solve this question.
andre [41]
  • <em>Answer:</em>

<em>x = - 2</em>

<em>y = 5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>2x + 9 = y</em>

<em>y = - 4x - 3</em>

<em> </em>

<em>equality</em>

<em>2x + 9 = - 4x - 3</em>

<em>2x + 4x = - 9 - 3</em>

<em>6x = - 12</em>

<em>x = - 12 : 6</em>

<em>x = - 2</em>

<em>replace x = - 2</em>

<em>2(-2) + 9 = y</em>

<em>- 4 + 9 = y</em>

<em>y = 5</em>

<em>Good luck !</em>

<em />

<em />

8 0
3 years ago
F(x)=1 |12.0-x<br> F(x)=0.2
Snezhnost [94]

Answer:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Step-by-step explanation:

4 0
4 years ago
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