ILL GIVE BRAINLIEST Segment AB is tangent to O T at B. What is the radius of OT?

Who do you think is correct?

Virty [35]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Given: p: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q? If x – 5 ≠ 10, then 4x + 1 ≠ 61. If 4x + 1 ≠ 61, then x – 5 ≠

AfilCa [17]

Answer: If x – 5 ≠ 10, then 4x + 1 ≠ 61

Justification:

1) The inverse of a conditional is negating both the hipothesis and the conclusion of the conditional, keeping the same sense of the implication.

2) This is the scheme (the symbol ~ is used to negate)

conditional: p → q
hypothesis: p
conclusion: q

negated hypothesis: ~p
negated conclusion: ~ q

inverse conditional: ~p → ~q

3) So, for the hypotheis p: x – 5 =10 and the conclusion q: 4x + 1 = 61, the conditional p→ q is:

if x - 5 = 10 then 4x + 1 = 61.

And the inverse is negating both the x - 5 = 10 and 4x + 1 = 61, leading to:

If x – 5 ≠ 10, then 4x + 1 ≠ 61, which is the answer.

8 0

4 years ago

Greg spent $4 on 5 packs of sport cards.

tino4ka555 [31]

Answer:

(a) Money spend on each pack will be $0.8

(b) Money send on each pack will be $0.2

Step-by-step explanation:

We have given that Greg spent $4 on 5 packs of spot card

(a) We have to find how much Greg spend on each pack

Cost of each pack will be $=\frac{4}{5}=$0.8$

(b) In this case it is said that Greg spent half of money

So money spent by Greg $=\frac{4}{2}=$2$

And he bought twice of pack than earlier

So number of packs he bought $=5\times 2=10$

So money spend on each pack will be equal to $=\frac{2}{10}=$0.2$

5 0

4 years ago

PLEASE NEED ANSWER FAST

ahrayia [7]

c or d for sure hope this helps

5 0

2 years ago

Emergency rooms have reason to suspect that visits increase on the weekends. A recent report indicates that Monday through Thurs

Rasek [7]

Answer:

No the facility dose not have the same pattern as the recent report at the 10% level

Step-by-step explanation:

To determine if the Facility have the same pattern ; Perform Chi squared test for Goodness of fit

state the hypothesis

H0 : μ = same pattern

Ha : μ ≠ same pattern

expected frequency ( E ) = proportion * summation of frequency

summation of frequency = 1000

degree of freedom = 7 - 1 = 6

Next : Calculate the expected frequency (E) , (O-E)²/E. given that the observed frequency and expected proportion is given

For Monday

expected frequency = proportion * frequency = 0.1 * 1000 = 100

(O-E)²/E. = ( 120 - 100 )^2 / 100 = 4.0.

observed frequency ( O ) , expected frequency ( E )

For Tuesday

E = 0.1 * 1000 = 100

(O-E)²/E = ( 130 - 100 )^2 / 100 = 9.0

Repeat same calculations for Wednesday through Sunday

Then perform Chi-squared test

X² = Σ(O-E)²/E = 63.642

∝ = 0.1

df = 6

hence P-value = 0.000 ( =chisq.dist.rt(test-stat,df)

since P-value < ∝ ; we will fail to reject Ha hence we reject H0

7 0

3 years ago