Question

The recipe calls for 5 parts strawberry juice to 3 parts water.Carmen would like to make 64 fluid ounces of the strawberry drink.How many fluid ounces of strawberry juice and water does carmen need?

Answer 1

We are given: Strawberry juice = 5 parts and

Water quantity = 3 parts .

Ratio of Strawberry juice to Water is = 5 : 3.

Total fluid ounces of the strawberry drink need to make = 64 ounces.

Let us assume strawberry juice need = x ounces.

So, the water would be need = Total fluid - strawberry juice  = 64 -x ounces.

The ratio of Strawberry juice to Water would reamain same 5:3.

So, we can setup a proportion now.

$\frac{x}{64-x}=\frac{5}{3}$

On cross multiplying, we get

x*3=5 *(64-x)

Distibuting 5 over (64-x), we get

3x = 5 * 64 - 5*x

3x = 320 -5x

Adding 5x on both sides, we get

3x+5x = 320-5x +5x

8x = 320

Dividing both sides by 8, we get

$\frac{8x}{8}=\frac{320}{8}$

x = 40

So, strawberry juice need = 40 ounces.

Water would be need = 64 - 40 = 24 ounces.

Therefore, 40 ounces of strawberry juice and 24 ounces of water carmen needs to make 64 fluid ounces of the strawberry drink.