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AlladinOne [14]
2 years ago
13

Given that

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0

Answer:

15.8

Step-by-step explanation:

First off, I think you mean area. You can't find the perimeter of a triangle with only two sides listed, neither can you find that side unless you have the perimeter.

1. Area of the triangle formula is axb/2= (9.9x3.2)/2, which when put in a calculator is 15.84.

2. Rounded to 1DP makes it 15.8

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Find each missing angle measure
timurjin [86]

Answer: angle 1=129 degrees

Step-by-step explanation:

180 - 99 - 30 = 51

all the angles of a triangle should add up to be 180 degrees

51+99+30=180

angle 1 is supplementary to the angle that is 51 degrees so it would be 129 degrees. 180-51=129

7 0
3 years ago
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Please help me solve this as soon as possible.
qaws [65]

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Step-by-step explanation:

6 0
3 years ago
HELPP!!! <br><br><br> What is the measure of ADC
Gwar [14]

72 degrees

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7 0
2 years ago
assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
using pythagorean inequalities, determine which set of the given three sides produces an acute triangle.
Kruka [31]
To solve this problem, you need to use the Phythagorean theorem c^2 is equal to the sum of a^2 and b^2. If a less than or equal to b and b is less than or equal to c or a^2 plus  b^2  is greater than c^2 then it is an acute angle. 
5 0
2 years ago
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