1. 77 mph
We already know they travel 38.5 miles in 30 minutes. So we multiply 38.5 x 2 because 30 minutes is 1/2 of an hour. 38.5 x 2 = 77
5. 8.5 minutes (8 minutes and 30 seconds) per mile
We have to divide 25.5 by 3 to know how many minutes it takes Jerry to run one mile.
8. 34.06
This one is kinda easier. We already know 34 is the whole number. 6 divided by 100 is 0.06, so we simply add 34 + 0.06
Answer:
2/3
Step-by-step explanation:
2 divided by 3 = 0.6666667 (keeps repeating)
That would be the average of total time paddled upstream & downstream . . . 12 miles / 7 hours = approx 1.71 miles per hr
Answer:
Option b that is 1.33 is the right choice.
Step-by-step explanation:
Given:
Mean rate of arrival
= 8 planes/hr
Service time =
minute/plane
Mean service rate
=
=
planes/hr
Applying the concept Poisson-distributed arrival and service rates (exponential inter-arrival and service times)(M/M/1) process:
We have to find mean number of planes waiting to land that is mean number of customers in the queue .
Mean number of customers in queue
.
⇒
Considering,
,
is also mean number of customers in service.
⇒ 
⇒ Plugging the values.
⇒ 
⇒ 
⇒
So,
Mean number of planes in holding and waiting to land = 1.33
a = amount invested at 7%
b = amount invested at 9%
we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000. We can also say that

since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.
![\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%20a%20%2B%20b%20%3D%2036000%5C%5C%5C%5C%200.07a%2B0.09b%3D2920%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20the%201st%20equation%7D%7D%7Ba%20%2B%20b%20%3D%2036000%5Cimplies%20%5Cunderline%7Bb%20%3D%2036000-a%7D%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B0.07a~~%20%2B%20~~0.09%28%5Cunderline%7B36000-a%7D%29~~%20%3D%20~~2920%7D%20%5C%5C%5C%5C%5C%5C%200.07a%2B3240-0.09a%3D2920%5Cimplies%203240-0.02a%3D2920%5Cimplies%20-0.02a%3D-320%20%5C%5C%5C%5C%5C%5C%20a%3D%5Ccfrac%7B-320%7D%7B-0.02%7D%5Cimplies%20%5Cboxed%7Ba%3D16000%7D~%5Chfill%20%5Cboxed%7B%5Cstackrel%7B36000~~%20-%20~~16000%7D%7B20000%3Db%7D%7D)