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Zepler [3.9K]
3 years ago
13

What is 7/8 - 2/3 in fractions?

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer: 5/24

Step-by-step explanation:

7/8 = 21/24      2/3= 16/24

21/24 - 16/24 = 5/24

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Jayce travels 30 miles per hour in her car.how many miles does she travel in 4 hours
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Answer:

120 miles

Step-by-step explanation:

30 miles per hour * 4 hours

120 miles

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Which of the following statements about rational numbers is not correct? А All whole numbers are also rational numbers. B All ra
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Step-by-step explanation:

  1. 1736-8166x71662=8177103 :D
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3 years ago
Solve: x=4+(4x-4)1/2
Damm [24]

Answer:

x = 10

Step-by-step explanation:

x = 4 + (4x-4) ^ (1/2)

First, we rewrite the expression:

x = 4 + (4x-4) ^ (1/2)

x = 2 (2+ (x-1) ^ (1/2))

x = 4 + 2 (x-1) ^ (1/2)

From here we get a solution for x = 10

To check it we substitute x = 10 in the expression:

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10 = 4 + 2 (3)

10 = 4 + 6

10 = 10

Answer:

The solution is:

x = 10

8 0
3 years ago
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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
4 years ago
How can I get to 75 using 7 5 6 3
eduard
63+5+7=75

Hope this helps
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3 years ago
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