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damaskus [11]
3 years ago
5

There are 4 different mathematics books and 5 different science books.In how many ways can the books be arrange on a shelf if th

ere are no restrictions
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

9!=362880 ways

Step-by-step explanation:

It is given that there are 4 different mathematics books and 5 different science books.

So basically there are 9 different books. So we have 9 choices for the first book, 8 choices for the second book, since we have placed the first one. We have 7 choices for the third book and so on. Therefore, we can arrange 9 different books in,

!9 ways, on solving !9 we get,

!9= 9 \times 8 \times 7 \times 6 ....\times 1= 362880

So there are 362,880 ways to arrange 9 different books if there are no restrictions.

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What percent of 150 is 162
Novay_Z [31]
To find a percentage of a number, you divide by that number.
So to find what percent of 150 162 is, you divide 162 by 150
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Now, to find the percentage, we take the decimal and move the point two places to the right.
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5 0
3 years ago
Please help I don’t understand.
Lina20 [59]
You can work out c first. That's probably the key to the whole problem.
The adjacent side to a 60o angle is 1/2 the hypotenuse
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Then c = 1/2 (4 sqrt(3)) 
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Next work out a.
a is in the same triangle as c and the hypotenuse.
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(sqrt(3))^2 = 3
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Now we need to work out d
The side opposite and the side adjacent  are equal when opposite a 45o angle in a right angle triangle
d = 6


The last thing to work out is be
a = 6
d = 6
c = ???

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c = sqrt(72)
c = sqrt(6*6*2)
c = 6 sqrt(2)

The answer should be B??? Check this out.
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