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damaskus [11]
3 years ago
5

There are 4 different mathematics books and 5 different science books.In how many ways can the books be arrange on a shelf if th

ere are no restrictions
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

9!=362880 ways

Step-by-step explanation:

It is given that there are 4 different mathematics books and 5 different science books.

So basically there are 9 different books. So we have 9 choices for the first book, 8 choices for the second book, since we have placed the first one. We have 7 choices for the third book and so on. Therefore, we can arrange 9 different books in,

!9 ways, on solving !9 we get,

!9= 9 \times 8 \times 7 \times 6 ....\times 1= 362880

So there are 362,880 ways to arrange 9 different books if there are no restrictions.

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HURRY I WILL GIVE BRAINLIEST which choice is equivalent to the product below √2x√5x√8
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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
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3 years ago
Please help? It's worth 16 points!!!!
ddd [48]

Answer:

I’m not too sure what your question is exactly but if your just trying to graph the two equations I can help u with that (:

Step-by-step explanation:

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3 years ago
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