The cube root of 2 is irrational. The proof that the square root of 2 is irrational may be used, with only slight modification. Assume the cube root of 2 is rational. Then, it may be written as a/b, where a and b are integers with no common factors. (This is possible for all nonzero rational numbers). Since a/b is the cube root of 2, its cube must equal 2. That is, (a/b)3 = 2 a3/b3 = 2 a3 = 2b3. The right side is even, so the left side must be even also, thatis, a3 is even. Since a3 is even, a is also even (because the cube of an odd number is always odd). Since a is even, there exists an integer c such that a = 2c. Now, (2c)3 = 2b3 8c3 = 2b3 4c3 = b3. The left side is now even, so the right side must be even too. The product of two odd numbers is always odd, so b3 cannot be odd; it must be even. Therefore b is even as well. Since a and b are both even, the fraction a/b is not in lowest terms, thus contradicting our initial assumption. Since the initial assumption cannot have been true, it must <span>be false, and the cube root of 2 is irrational.
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Answer:
3/10
Step-by-step explanation:
fouth grade students at Estrabook make up 0.3 percents of the students at school
The fraction is therefore equivalent to
= 3/10
(3n2-5n+6)+(-8n2-3n-2)
3n2-5n+6-8n2-3n-2
Collect like terms
3n2-8n2-5n-3n+6-2
-5n2-8n+4
Answer:
<em>m-parallel</em>: -2/3
Sorry if I'm wrong though.
First, is to raise the price to earn profit. Second, is to maintain the price to maintain the number of buyers. Third, is to maintain the price but to lessen the chicken feed inside a bag. Fourth, to tell the customers first that you will raise the price of your product.
