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kompoz [17]
3 years ago
11

Find the average rate of change for the given function over the indicated values of x. If necessary, round your final answer to

two decimal places.
f(x)=x^2+6x, where x goes from 5 to 7.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

The average rate of change of the function in this interval is of 18.

Step-by-step explanation:

The average rate of change of a function f(x) in an interval from a to b is given by:

A = \frac{f(b) - f(a)}{b - a}

In this question:

f(x) = x^2 + 6x

Where x goes from 5 to 7.

This means that b = 7, a = 5. So

f(7) = 7^2 + 6(7) = 49 + 42 = 91

f(5) = 5^2 + 6(5) = 25 + 30 = 55

The rate of change is:

A = \frac{f(7) - f(5)}{7 - 5} = \frac{91 - 55}{2} = 18

The average rate of change of the function in this interval is of 18.

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A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
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Answer:   (0.367,\ 0.473)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} is the sample proportion, n is the sample size , z_{\alpha/2} is the critical z-value.

Given : Significance level : \alpha:1-0.99=0.01

Sample size : n= 85

Critical value : z_{\alpha/2}=2.576

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Now, the  99% confidence level will be :

\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)

Hence, the  99% confidence interval estimate of the true proportion of families who own at least one DVD player is  (0.367,\ 0.473)

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