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Alecsey [184]
2 years ago
15

2. Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 1

2ft, what will the total area of the walkway be? Hint: Draw a picture!
can anybody help me​
Mathematics
1 answer:
Yuki888 [10]2 years ago
4 0

The area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

The dimensions of the garden = 10 ft by 12 ft

Area = 10×12 = 120 square feet

The width of the walkway = 3 feet

If we create a walkway around the garden, it will be a rectangle around the garden.

So the dimensions for the bigger rectangle = (3+10+3) ft by (3+12+3) ft

Area of the bigger rectangle = 16×18 = 288 square feet

So the area of the walkway = 288 - 120 = 168 square feet

Thus, the area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

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Answer:

An equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

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Step-by-step explanation:

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y = mx+b

where m is the slope and b is the y-intercept

Given the equation

6x+y=6

Writing in the slope-intercept form of the line equation

y = -6x + 6

comparing with the slope-intercept form of the line equation

y = mx+b

Thus, the slope of line = m = -6

We know that the parallel lines have the same slopes.

Thus, the slope of the parallel line is also -6.

As the line passes through the point (2,−5).

Thus, using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope and (x₁, x₂) is the point

substituting the values m = -6 and the point (2,−5)

y-y_1=m\left(x-x_1\right)

y - (-5) = -6 (x - 2)

y+5=-6\left(x-2\right)

subtract 5 from both sides

y+5-5=-6\left(x-2\right)-5

y=-6x+7

Therefore, an equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

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Mr. Wilson is giving his students a vocabulary test tomorrow over all the terms they have learned from this semester. Today, he
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