Answer:
70
Step-by-step explanation:
First, set up the ratio of c:t, which is 12:8. Then set up your new ratio of c:t, which is 105:?. The way I find the easiest is to divide 105 by 12, which is 8.75, then multiply that by 8, which is 70. To check if it's right, just divide 12 by 8, and 105 by 70, and if they're the same number, you've got it right.
Ps. I'm guessing you meant to ask the minimum number of trucks, not cars.
No because the stupidity of you can not calculate
Answer:

Step-by-step explanation:
5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7
⇔ x = ln7/(2ln5-ln7)
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
1)
m = 3√2√2
= 6
n = a
= 3√2
<u>Answer = </u><u> </u><u>D</u><u>)</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>,</u><u> </u><u>n</u><u> </u><u>=</u><u> </u><u>3</u><u>√</u><u>2</u>
2)
m = n = a
m = 3
n = 3
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>