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Mandarinka [93]
2 years ago
10

Give your answer in its simplest form.

Mathematics
1 answer:
andrew-mc [135]2 years ago
3 0

Answer:

Is the question to develop the equation for the straight line shown?

If so,<u> y = (3/4)x + b</u>

Step-by-step explanation:

Look for an equation with the form y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

Calculate Slope using the Rise/Run.

Pick any two points.  I chose (-4,0) and (4,6).

Going from left to right:

Rise = (6 - 0) = 6

Run = (4 - (-4)) = 8

Slope is Rise/Run, 6/8 or 3/4

So we have:  y = (3/4)x + b

We can see that the y-intercept, b, is 3 (the value of y when x = 0).

The full equation becomes :<u>  y = (3/4)x + 3 </u>

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At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

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If you're looking for the dashed line, here it is.


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