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adoni [48]
2 years ago
8

Can someone please help will mark brainlist

Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

You can complete the mission 5 times before you earn less than 400 points.

Explanation:

100(0.8)^n^-^1 < 400

(0.8)^n^-^1 < 0.4

log 0.8^n < log 0.32

n > 5.1

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Translate each sentence into an equation. Then find each number.
PIT_PIT [208]

Answer:

10 - 3n = 31

n = -7

Step-by-step explanation:

10 - 3n = 31

-3n = 31 - 10

-3n = 21

n = 21/-3

5 0
3 years ago
a swimmer swam 48 kilometers in d days. What is the value of the d if the swimmer swam an average of 3.2 kilometers daily?
lianna [129]
Time= distance/speed

=48/3.2= 15
6 0
3 years ago
PLEASE HELP! A city has a population of 390,000 people. Suppose that each year the population grows by 6.25%. What will the popu
Vaselesa [24]

Answer: The population will be 536,250 people

Step-by-step explanation:

5 0
3 years ago
76 POINTS IF YOU CAN ANSWER THIS!!!The amount of water an electric dishwasher uses to wash dishes varies directly with the numbe
Vladimir79 [104]

Answer:

80

Step-by-step explanation:

Since you need 10 loads you know that for 4 loads you use 32 gallons. And to go from 4 to 10 you divide 10 and 4 to get an answer of 2.5. So all you have to do is multiple 32 gallons by 2.5 to then get an answer of 80.

5 0
3 years ago
Read 2 more answers
Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(
Mumz [18]
The given equations are
x(t+1)-4t \sqrt{x} =9            (1)
2y+4y^{3/2}=t^{3}+t           (2)

When t=0, obtain
x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means \frac{dx}{dt}.

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1 
y'(0) = 1/2.
Here, y' means \frac{dy}{dt}.

Because \frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}, obtain
\frac{dy}{dx} |_{t=0}\, =  \frac{1/2}{3}= \frac{1}{6}

Answer:
The slope of the curve at t=0 is 1/6.



3 0
3 years ago
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