Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
Answer: He can raise up to 40 goats and 100 llamas.
Step-by-step explanation:
Hi, to answer this question we have to write system of equations with the information given:
The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)
4x +10y ≤ 800 (acres)
The amount of veterinary care (in $) each goat needs (110) multiplied by the number of goats (x); plus The amount of veterinary care each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)
110x +88y ≤ 14,520 (cost)
Multiplying the first equation by 27.5, and subtracting the second equation to the first one:
110x + 275y ≤22,000
-
110x +88y ≤ 14,520
____________
187y ≤ 7480
y ≤ 7480/187
y ≤ 40
Replacing y in the first equation
4x +10(40) ≤ 800
4x +400 ≤ 800
4x ≤ 800-400
4x ≤ 400
x ≤ 400/4
x ≤ 100
Hey there!
if i am doing this correct it should be
17/50, let me explain!
.34 is 34/100 and both of these numbers are even, thus you can divide it by 2 which will give you 17/50
Hope This Helps!!!
One expression u can use is 900÷30
Round 868 up to 900
and round 29 up is 30