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djyliett [7]
3 years ago
12

What are the coordinates of the vertex of the parabola described by the equation below? y = -7(x - 4)2 - 5

Mathematics
2 answers:
pochemuha3 years ago
7 0
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)


lesantik [10]3 years ago
4 0

Answer:

The answer is (4, -5), Hope you have a good day and pass the exam.

Step-by-step explanation:

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Solve this system of equations.
nata0808 [166]

x = 8, y = 0

y=\frac{1}{2}x-4

y=-\frac{1}{4}x+2

We substitute y=\frac{1}{2}x-4 into the y for y=-\frac{1}{4}x+2, and we get:

\frac{1}{2}x-4 = -\frac{1}{4}x+2

+\frac{1}{4}x   +\frac{1}{4}x

\frac{3}{4}x -4 = 2

  +4  +4

\frac{3}{4}x = 6

(4)\frac{3}{4}x = 6 (4)

The 4's cross out and we get:

3x = 24

/3     /3

x=8

Not we substitute x(8) into one of our original equations: y=\frac{1}{2}x-4

y=\frac{1}{2}x-4

y=\frac{1}{2}(8)-4

y=4-4

y-0

We get our final answer: (8,0)

Hope that helps!

3 0
2 years ago
Read 2 more answers
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