All categories

3 years ago

What are the coordinates of the vertex of the parabola described by the equation below? y = -7(x - 4)2 - 5

2 answers:

7 0

To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)

lesantik [10]3 years ago

4 0

Answer:

The answer is (4, -5), Hope you have a good day and pass the exam.

Step-by-step explanation:

You might be interested in

Need some help with these problems please.

goldenfox [79]

Answer:

See below.

Step-by-step explanation:

Divide the leading terms:

6x^4 / 2x^2 = 3x^2

3x2 is a parabola so the long run is

as x ---> +/- infinity r(x) ----> + infinity. (answer).

10,000x^3 / 50 x^3

= 200.

So r(x) as a horizontal asymptote at y ( r(x)) = 200. (answer).

3 0

3 years ago

Write the simplest polynomial function with the zeros..?

zubka84 [21]

All u do is add up until u get ur answer

7 0

2 years ago

9100 dollard placed into an account with an annual intrest of 5% to the neareast year how long will it take for the account to v

shusha [124]

Answer:

81 years

Step-by-step explanation:

The answer is 81 because 5% of 9100 is 455 and 36900 divided by 455 is rounded to 81.

4 0

3 years ago

Miss Gonzales opened an account with a deposit of $2,000,

tatuchka [14]

Answer:

22.5

Step-by-step explanation:

8 0

3 years ago

What is the equation of the line that passes through the point (-2,5) and has a<br> slope of -4?

adoni [48]

Answer:

$\boxed {\boxed {\sf y= -4x -3}}$

Step-by-step explanation:

We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.

$y-y_1= m(x-x_1)$

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).

m= -4
x₁= -2
y₁ = 5

Substitute the values into the formula.

$y-5 = -4 (x--2)$

$y-5 = -4 (x+2)$

We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.

First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.

$y-5=( -4 *x ) + (-4* 2 )$

$y-5 =(-4x)+ (-8)\\y-5= -4x -8$

5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.

$y-5 =-4x -8 + 5$

$y= -4x -3$

The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.

6 0

3 years ago