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IgorLugansk [536]
2 years ago
9

A path in the park is 15 kilometers in. a trash bin is placed every 1/3 kilometers how many trash cans are along the path ?

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
8 0

Answer:

45

Step-by-step explanation:

There are is a trash can every 1/3 km, so there are 3 in 1 km. There are 15 km, so 15 km*3=45 trash cans.

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Please help<br><br> Write an inequality for the given graph
Oduvanchick [21]

Answer:

 y < 1/2x - 3

Step-by-step explanation:

You can write the inequality equation for the graph using the form y = mx + b. The inequality line has a y-intercept at (0,-3). This means b = -3. It also has a slope of 1/2 since the line moves up 1 and over 2 to the next point on the line.

This means the lines equation is y = 1/2x - 3. But since this is an inequality, you must use an inequality sign. Since the line is dashed it is not equal to. Your options are < and >.  Use the point (0,0) to test which sign is appropriate.

y < 1/2x - 3                      y > 1/2x - 3

0 < 1/2(0) - 3                   0 > 1/2(0) - 3

0 < -3                              0 > -3

The answer is y < 1/2x - 3 since (0,0) doesn't make it true and (0,0) is not shaded in the graph. This means it is not a solution.

8 0
3 years ago
What are the domain and range of g of x equals the square root of the quantity x plus 4?
Vadim26 [7]

It is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

<h3>What are the domain and range of a function?</h3>
  • The domain of a function is the set of values that can be plugged into it. This set contains the x values in a function like f(x).
  • A function's range is the set of values that the function can take.
  • This is the set of values that the function returns after we enter an x value.

To find the domain and range:

  • The given function in the problem is: g(x)=\sqrt{x+4}
  • Because the square root function does not exist for negative numbers, the domain is denoted by: x+4 ≥ 0 → x ≥ -4
  • Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).
  • The range of the square root function is x ≥ 0, which remains the same as there are no vertical translations.

Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

Know more about the range here:

brainly.com/question/26098895

#SPJ4

The complete question is given below:

What are the domain and range of g of x equals the square root of the quantity x plus 4?

(A) D: [4, ∞) and R: [0, ∞)

(B) D: (–4, ∞) and R: (–∞, 0)

(C) D: [–4, ∞) and R: [0, ∞)

(D) D: (4, ∞) and R: (–∞, 0)

3 0
1 year ago
IV
nikitadnepr [17]
The answer is all real numbers
5 0
3 years ago
A computer store changed the price of a laptop. It was originally $900, but now it is $1,100.Find the percent of change
tigry1 [53]

Answer:

The percent of change is 22.22%.

Step-by-step explanation:

You can calculate the percent of change by subtracting the original number from the final number and dividing that by the original number. Then, you have to multiply the result for 100:

percent of change=((1,100-900)/900)*100

percent of change=(200/900)*100

percent of change=22.22%

According to this, the answer is that the percent of change is 22.22%.

7 0
3 years ago
The seats at a local baseball stadium are arranged so that each row has five more seats than the row below it. If there are four
brilliants [131]

Answer:

Thus the last row has 119 seats.

The total number of seats in 24 rows = 1476

Step-by-step explanation:

The number of seats in each row make an arithmetic series. We will use arithmetic equation to find the number of seats in last row:

An = a1+ (n-1)d

An = 4+(24-1)5  

An = 4 + (23)(5)  

An = 4 + 115  

An = 119

Thus the last row has 119 seats.

Now to find the sum of seats we will apply the formula:

Sn = n(a1 + an)/2

Sn = 24(4+119)/2  

Sn = 24(123) /2  

Sn = 1476 .....

The total number of seats in 24 rows = 1476....

6 0
3 years ago
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