(60 · x^20 · y^24)/(30 · x^10 · y^12)
= (60/30) · (x^20/x^10) · (y^24/y^12)
= 2 · x^(20-10) · y^(24-12)
= 2 · x^10 · y^12
Answer: 2 x^10 y^12
Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%
Solve for n by simplifying both sides of the equation, then isolating the variables.
n=54
Hope I helped
What number is 12 1/2 % of 64?
64 * 0,125 = 8
least = 4
greatest= 8
4.4 rounds to 4
7.7 rounds to 8
<em>if the number is less then or equal to 4 it rounds down </em>
<em>if the number is equal to or greater than 5 it rounds up</em>