I need help with this trigonometry problem.

Mathematics

1 answer:

irina1246 [14]2 years ago

4 0

The sum of all 3 angles in a triangle is 180
180-44=136
And you know that angle A is over 90 degrees so I believe it is 100 leaving angle b to be 36

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Pls help me with this

kvasek [131]

Answer:

1st one is positive

2nd one is negative

3rd one is negative

4th one is positive

Step-by-step explanation:

7 0

2 years ago

Suppose you have a standard deck of 52 cards. What is the probability that if you select a card at random that it does not have

mr Goodwill [35]

0.92

Step-by-step explanation:

There are 4 cards in a deck of 52 cards that has a face value of 3. That means that the other 48 cards don't have a face value of 3. Therefore, the probability of picking a card of this deck that doesn't have a face value of 3 is

$P =\dfrac{48}{52} = 0.92$

4 0

2 years ago

Nadine can send or receive a text message for $0.15 or get an unlimited number for $5.00. Write and solve an inequality to deter

34kurt

Answer:

0.15*t < 5.00

33 texts

Step-by-step explanation:

given : $0.15 per text; unlimited cost is $5.00

# of texts = t

0.15*t < 5.00

t < 33.33; since you cannot make 33.33 texts i will round down to 33 texts.

Basically you can send or receive up to 33 texts and it will be cheaper than $5.00

0.15(33) = $4.95

at 34 texts, 0.15(34) = $5.10

8 0

3 years ago

Does anyone know how to do this ?

goldenfox [79]

Answer: D) 32

Step-by-step explanation:

The area of a parallelogram equals its base times its height. Substitute the base and area into this formula to solve for the height:

A=bh

40=(5)(h)

h=8

If ABCD is a parallelogram, opposite sides are parallel, so AB is parallel to DC. If AB is parallel to DC, EB is parallel to DC. Since EB is parallel to DC, quadrilateral EBCD has at least one pair of parallel sides, making it a trapezoid. The area of a trapezoid is equal to $\frac{h(b_{1}+b_{2}) }{2}$ where h is the height, $b_{1}$ is one base, and $b_{2}$ is the other base. Plug the necessary values into the formula: