Answer:
125.4
Step-by-step explanation:
Given

Required
Round to 1 decimal place
Up till the first decimal place, the number is:

The digit after .3 is 5
The conditions for approximation are:
- If n > 4, approximate to 1
In this case: 5 > 4, so we approximate to 1
Add this "1" to the last digit of 125.3. This becomes 125.4
<em>Hence: when the number is approximated to 1 decimal place, the digit is 125.4</em>
2s+5<span>≥49
First: Subtract 5 on both sides
You'll get: 2s </span><span>≥ 44
Last: Divide each side by 2 so your s would be alone
You'll get: s </span><span>≥ 22 <That would be your answer
HOPE THIS HELPS! ^_^</span>
Answer: The equation of the sphere with the center and radius

b) The intersection of this sphere with the y z-plane the x- co-ordinate
is zero(i.e., x = 0 )
Step-by-step explanation:
a) The equation of the sphere having center (h,k,l) and radius r is

Given center of the sphere (3, -9, 3) and radius 5

on simplification , we get solution


Final answer :-

b) The intersection of this sphere with the y z-plane the x- co-ordinate
is zero(i.e., x = 0 )

Answer:
x = $3
y = $4
Step-by-step explanation:
We need to know the prices of gravel and peas. We can find the price by using equations and graphing them.
Let X be the price of the sand
Be and the price of pea gravel
In the first purchase we have:

In the second purchase we have

Both relations represent the equation of a line. In the graphic shown, these lines are drawn. In this case the interception between both lines represents the price of each product, and the solution of the problem. You can see that the lines intersect at point (3 4). This means that the price of each bag of sand is $ 3, and the price of a bag of pea gravel is $ 4.