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agasfer [191]
3 years ago
7

a rectangular parking lot has length that is greater than the width the area of the parking lot is 160 square yards find the len

gth and the width use formula area=length*width the parking lot length
Mathematics
1 answer:
MissTica3 years ago
3 0
Let 'w' represent the width of the parking lot, then 'w+6' represents its length



area = width * length



160 = w * (w+6)

solving for 'w' we have a positive value of w=10



10+6=16



the width of the parking lot is 10 yards, the length of the parking lot is 16 yards
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One month Justin rented 3 movies and 5 video games for a total of $39. The next month he rented 9 movies and 7 video games for a
Leviafan [203]

Let m be the rental cost for movies.

Let v be the rental cost for video games.

We have the following system of linear equations:

3m + 5v= 38

6m + 2v = 26

Multiply the first equation by 2

6m + 10v = 76

6m + 2v = 26

Subtract the both equations.

8v = 50

Divide both sides by 50.

v = 6.25

Plug this value into any of the two equations to solve for m.

You get m=2.25

The rental cost for a movie is

<h2>$2.25</h2>

The rental cost for a video game is

<h2>$6.25 </h2>

Have an awesome day! :)

5 0
2 years ago
Solve for n. 8 3/4 + n + 2 3/8 + 4 1/2 = 23 1/8 A. 7 1/2 B. 8 3/8 C. 15 5/8 D. 8 4/8
Sonbull [250]
You can change all of these to decimals and then solve or get common denominators.
8.75 + n + 2.375 + 4.5 = 23.125
15.625 + n = 23.125
Subtract 15.625 from both sides
n = 7.5
8 0
3 years ago
HELP!!! PLEASE I WOULD APPRECIATE IT SO MUCH!!
Novay_Z [31]
Try multiplying if it doesn't work divide
8 0
3 years ago
Need help on number 25 and 26 can you please explain how you got the answer thanks!:)
Westkost [7]
In both problems, the sum of side lengths is the perimeter. Opposite sides of a parallelogram (or rectangle) are equal in length, so you can find the perimeter by doubling the sum of adjacent sides.

25. 2(x +(x +15)) = (x +45) +(x +40) +(x +25)
.. 4x +30 = 3x +110 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 80 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+30
.. 4x +30 = 4*80 +30 = 240
The perimeter of each is 240 units.

26. 2(x +(x +2)) = (x) +(x +6) +(x +4)
.. 4x +4 = 3x +10 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+4
.. 4x +4 = 4*6 +4 = 28
The perimeter of each is 28 units.
6 0
3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
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