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andrew11 [14]
2 years ago
8

A toy factory manufactures d dolls every hour.Each dolls costs e cents.How much money will the factory spend in costs for manufa

cturing dolls in 7 hours and 30 minutes?​
Mathematics
1 answer:
klemol [59]2 years ago
5 0

Answer:

in 7hours and 30 mn the cost will be (7.5×d×e) cents

Step-by-step explanation:

\begin{matrix}\text{Time} &1h&7.5h\\ \text{number of dolls} &d&7.5\\ \text{Cost} &d\times e&7.5\times d\times e\end{matrix}

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Answer:

C. 101 - 5(n - 1)

Step-by-step explanation:

d = (26 - 71)/(16 - 7)

d = -45/9

d = -5

a7 = a1 + (7-1)(-5)

71 = a1 - 30

a1 = 101

an = 101 + (n - 1)(-5)

an = 101 - 5(n - 1)

4 0
3 years ago
Read 2 more answers
Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t
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Answer:

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

\hat p=0.71 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.69 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:  

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.675)=0.047  

If we compare the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns  is not significantly higher than 0.69.  

5 0
3 years ago
Summerfield has a population of 26,000 people. The town has been seeing its population decline by 10% every year. If this trend
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Answer:

should be 1007

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6 0
3 years ago
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Mice21 [21]
483 divided by 23 = 21
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3 years ago
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On selling 250 cascades, a man had an equal gain to the selling price of 25 cascades. Find his gain percent
Jet001 [13]

Answer:

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Step-by-step explanation:

The selling price is 250

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Therefore the gain can be calculated as follows

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= 11.11%

Hence the gain is 11.11%

6 0
3 years ago
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