Answer:
Step-by-step explanation:
either do 23 x23
or
23 x 16 ( do this first )
1/6
Step-by-step explanation:
Answer:
x=−3
Step-by-step explanation:
2(6x+1)−4(x−5)=−2
Step 1: Simplify both sides of the equation.
2(6x+1)−4(x−5)=−2
(2)(6x)+(2)(1)+(−4)(x)+(−4)(−5)=−2(Distribute)
12x+2+−4x+20=−2
(12x+−4x)+(2+20)=−2(Combine Like Terms)
8x+22=−2
8x+22=−2
Step 2: Subtract 22 from both sides.
8x+22−22=−2−22
8x=−24
Step 3: Divide both sides by 8.
8x/8=−24/8
Answer:
x = -5, x = -6
Step-by-step explanation:
After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.
The denominator will be zero when ...
x + 5 = 0 . . . . at x = -5
x + 6 = 0 . . . . at x = -6
Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
