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Tema [17]
3 years ago
6

HELPP: find 'x' in the following

Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:

Aproximately 7.5 cm

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Write a statement that correctly interprets the confidence interval. Choose the correct answer below. A. One has 90​% confidence
poizon [28]

Answer:

B. <em>There is a 90​% chance that the true value of the population proportion will fall between the lower bound and the upper bound. </em>

Step-by-step explanation:

A. <em>One has 90​% confidence that the sample proportion is equal to the population proportion. </em>

Confidence interval gives an interval estimate, not an equality

B. <em>There is a 90​% chance that the true value of the population proportion will fall between the lower bound and the upper bound. </em>

<em>Ture. </em>

<em>C.</em><em> One has 90​% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. </em>

Also true but <em>One has 90​% confidence is not good interpretation. </em>

<em>D</em><em>. 90​% of sample proportions will fall between the lower bound and the upper bound.</em>

<em>Lower bound and upper bound is given to estimate population proportion. </em>

4 0
3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ&gt;0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\&#10;\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\&#10;\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\&#10;\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\&#10;\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\&#10;\mathsf{17\,sin^2\,\theta=1}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
How do you find the area of the base in a cylinder
Llana [10]

Answer:

area is easy because its always the  Length times the Width of something  so after you get the area you times it by the base which is the bottom part of the cylinder

Step-by-step explanation:

so you would just get the length and the Width and multiply them and... theres your answer!

6 0
3 years ago
What percent of campers are over the age of 14?
Ierofanga [76]

Answer: 45%

Step-by-step explanation: There's 9 people over the age of 14. And 9 divided by the total number, 20, gives you 0.45. 0.45 multiplied by 100 is 45.

7 0
3 years ago
What is 5.5 converted to miles?
Otrada [13]

Answer: 3.42 miles

Step-by-step explanation:

5.5 cm converts to 3.41754e-5 miles

5 0
3 years ago
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