5 —— —— i need help!! ————- math geniuses pls help me!

Mathematics

1 answer:

34kurt1 year ago

5 0

Answer:

Step-by-step explanation:

x = 7 cos (2pi/3) y = 7 sin (2pi/3)

x = -7/2 y = 7 sqrt(3) /2

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$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
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A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR? pythagorus theorem

algol13

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²