Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
Answer: 6+10b
Step-by-step explanation: Subtract 1 and 2 from 9, and you will end up with 6. 3b and 7b is 10b when added together. I hope this helps. Have a nice day.
Answer:
% error = 3.3%
Step-by-step explanation:
Percent Error Formula:
% error = ( (MeasuredValue - AcceptedValue) / AcceptedValue ) * 100
% error = ( (12.7 - 12.3) / 12.3 ) * 100
% error = (0.4/12.3) * 100
% error = (0.03252033) * 100
% error = 3.25203252
% error = 3.3%